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```				   calcium carbonate reacts with azueous HCL to give cacl2 and co2 acoording to the reaction,caco3+2hcl--->cacl2+co2+h2o.
what mass of caco3 is required to react completely with 25 ml of 0.75M hcl?
```

5 years ago

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```										Dear Sundhar ,

M = moles /v ( litre )
moles HCL = 25 * .75/1000 = 0.0187
now, mole CaCO3 = moles HCL/2 = 0.0093
mass = moles * molar mass (CaCO3)

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```
5 years ago

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