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calcium carbonate reacts with azueous HCL to give cacl2 and co2 acoording to the reaction,caco3+2hcl--->cacl2+co2+h2o.

what mass of caco3 is required to react completely with 25 ml of 0.75M hcl?

5 years ago


Answers : (1)


Dear Sundhar ,


 M = moles /v ( litre )

moles HCL = 25 * .75/1000 = 0.0187

now, mole CaCO3 = moles HCL/2 = 0.0093

mass = moles * molar mass (CaCO3)


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Anil Pannikar

IIT Bombay

5 years ago

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