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Akhilesh Gandhi Grade: 11
        

if the K.E of electron is Increased by 4 times then Broglie wavelength associated with it would become????????


 

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

de broglie wavelength (lamda)L=  h/(2mKE)1/2                 ..............1          


 


 here h is planks constant, m is mass of electron  & KE is kinetic energy...


 


     from eq 1


                      L(lamda) is inversly proportional to (KE)1/2


                    L/L1   =   {(KE)f /(KE)i}1/2          


(KE)f = 4(KE)i   (given)


 so    L/L1 = 2   or


        L1 = L/2


 it means de broglie wavelength of electron is decreased to half times the  initial value....


 

6 years ago
PRASHANT MISHRA
4 Points
										

According to De BROGLIE,


wavelength=h/root 2Em


where h....Planck constant


E.... Kinetic energy, m= mass of electron


Thus, when kinetic energy associated with electron is increased four times, then wave length would become half of the initial value.

6 years ago
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