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1 mole of N2H4 loses10 moles of electrons to form a new compond Y. assuming that all nitrogen appears in the new compound , what is the oxidation state of nitrogen in Y ? [there is no change in the oxidation state of hydrogen.]
Hi
Oxidation state of NItrogen in n2h4 is -2. 2(-2) + 4(+1)= 0
therefore two N makes it -4 , since they lose 10 e- , hence total charge is +6, and since H is still +1 , Two N divides the +6 .
then ox state of N is +3 in the new compound Y.
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