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Akhilesh Gandhi Grade: 11
        

what is the final concentration of all the ions when when following are mixed:-50ml of .12M Fe(no3)3  ,100ml of .10M Fecl3 and 100ml of .26M Mg(no3)2??

6 years ago

Answers : (1)

ABHISHEK JAIN AskiitiansExpert-IITD
20 Points
										

dear Akhilesh,


Molarity = moles of solute/ volume of solution(lit.)


         1)  moles of Fe(no3)3 = .12×50/1000


     1 mole of Fe(no3)3 contains 4 ions


therefore .12×50/1000 contains = .12×50/1000×4 ions


                                              =.024 ions


2) moles of Fecl3 = 100×.10/1000


therefore 100×.10/1000 contains = 100×.10/1000×4 ions


                                               =.040 ions


3) in the same way moles of Mg(no3)2 = 100×.26/1000


       and ions = 100×.26/1000×3


                    =.078 ions


Total ions = .024+.040+.078


               =.142


Total concentration of ions = total moles/ total volume(lit.)


                                      =.142/.25


                                      =.568 M

6 years ago
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