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				   how to find hybridisation?i want shortcut or any trick
				   

6 years ago

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Answers : (14)

										

Dear Pradeep


Following is the way to find hybridisation


1st step    :  count the no. of valence electrons[ V ]
2nd step   :   now divide V by 8 ,if V >8
                    or
                    divide V by 2 ,if  V <=8                                   -[1]
                    if the remainder is still  not zero then
                   again divide it by 2,                                         - [2]
                   therefore the final value = quotient in 1+ quotient in 2
                  as    shown in the example
3rd step    :  compare the above obtained value with the table given below :-
                   sp          -   2
                   sp2        -   3
                   sp3        -   4
                   sp3d      -   5
                   sp3d2    -   6
                   sp3d3    -   7
ex:- for  c2h6
step  1   -   2[4 ] + 6[1] = 4+6=10
step  2    -   as 14>8 
                   14/8, quotient=1  as remainder  = 6 which is not equal to zero
                    therefore 6 / 2   quotient=3
                  therefore final value=1+3=4
                   comparing with the table given above
                   the hybridisation is sp3.
note -  this is not applicable  to all compounds


All the best

AKASH GOYAL
AskiitiansExpert-IITD

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6 years ago
										

you can use HON rule


 according to this 2X=number of electrons in valence shell-charge+number of monovalent atoms attached(Cl,H etc)


  if x comes 2 then hybridisation is sp


  if 3 then sp2 ,if 4 then sp3 and so on


 example ..hybridisation of NH4+


          2x=5+4-1


            x=4 so hybridisation is sp3


 approve my ans if u like

6 years ago
										

to find the hybridisation of an element in a given compound  first count the number of σ bonds and the no. of lone pairs present then it becomes the steric no of the element then just get the hybridisation. hybridisation forsteric no.


2--sp


3--sp2


4--sp3


5--sp3d


6--sp3d2


7--sp3d3


thats it the short cut count the no of σ bonds  and ya got the hybridisation


note:- its applicable to all compounds provided ya know the structure or no of atoms connected to the given atom whose hybridisation is to be found hers an example check out


1745_22795_cr2o7.JPG


here no of σ bettween Cr and O are 5 there fore the hybridisation is sp3d


note sigma bond are the primary bonds so whereever you see double bond then there are one sigma and one pi bonds


for lone pair take NH3 nitrogen has 1 lone pair and 3 σ bonds thus the hybridisation is sp3

6 years ago
										

can u please tell me how to find out the hybridisation for ph3 please and aso give me the explanation thank you

3 years ago
										Just count the no.of sigma bonds and lone pairs (if any) Thats all!
										
2 years ago
										What is the hybridization of I 3 minus?
										
2 years ago
										for any compound identify the central atom then count the no. of sigma bonds and no. of lone pairs on it and then add them. eg: in a CO2 molecule carbon is the central atom, no. of sigma bonds are 2 and no. of lone pairs are 0 then sum is 2 which means sp hybridization is there.
										
2 years ago
										for a shortcut. find the no of atoms attached to it. then write its corresponding hybridisation. if central atom is attached to 2.. sp.. 3..sp2.. so on
										
2 years ago
										Countcount the no. Of sigma bond and no of lone of atom whose hybridisation is to be predicted . All single bonds ate sigma , in amultiple bond one will sigma others be pie
										
2 years ago
										Accr to VSEPR theory H={V+M-C+A} the simplest method 
V = valence electrons in central atom
M=number of univalent atom attached to central atom
C=charge on cation
A=charge on anion
2 years ago
										
dont,t get confused just no. of sigma bond + lone pairs ,if sum is
 

2--sp

 

3--sp2

 

4--sp3

 

5--sp3d

 

6--sp3d2

 

7--sp3d3

2 years ago
										
but what if remainder is not zero. it wont be divisible by 2 ex. CH3
one year ago
										
hybridization of h3po3
 
one year ago
										
calculate no. of bond pairs[sigma bonds only] and lone pairs and add them..the no. u get is the hybridisation of that atom...if h=2=sp,,if h=3=sp2,,if h=4=sp3,,if h=5=sp3d and so on
one year ago

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