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```				   how to find hybridisation?i want shortcut or any trick
```

6 years ago

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```										Dear Pradeep
Following is the way to find hybridisation
1st step    :  count the no. of valence electrons[ V ]2nd step   :   now divide V by 8 ,if V >8                    or                    divide V by 2 ,if  V <=8                                   -[1]                    if the remainder is still  not zero then                   again divide it by 2,                                         - [2]                   therefore the final value = quotient in 1+ quotient in 2                   as    shown in the example3rd step    :  compare the above obtained value with the table given below :-                   sp          -   2                   sp2        -   3                   sp3        -   4                   sp3d      -   5                    sp3d2    -   6                   sp3d3    -   7ex:- for  c2h6step  1   -   2[4 ] + 6[1] = 4+6=10step  2    -   as 14>8                     14/8, quotient=1  as remainder  = 6 which is not equal to zero                    therefore 6 / 2   quotient=3                   therefore final value=1+3=4                   comparing with the table given above                    the hybridisation is sp3.note -  this is not applicable  to all compounds
All the bestAKASH GOYALAskiitiansExpert-IITDPlease feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
```
6 years ago
```										you can use HON rule
according to this 2X=number of electrons in valence shell-charge+number of monovalent atoms attached(Cl,H etc)
if x comes 2 then hybridisation is sp
if 3 then sp2 ,if 4 then sp3 and so on
example ..hybridisation of NH4+
2x=5+4-1
x=4 so hybridisation is sp3
approve my ans if u like
```
6 years ago
```										to find the hybridisation of an element in a given compound  first count the number of σ bonds and the no. of lone pairs present then it becomes the steric no of the element then just get the hybridisation. hybridisation forsteric no.
2--sp
3--sp2
4--sp3
5--sp3d
6--sp3d2
7--sp3d3
thats it the short cut count the no of σ bonds  and ya got the hybridisation
note:- its applicable to all compounds provided ya know the structure or no of atoms connected to the given atom whose hybridisation is to be found hers an example check out

here no of σ bettween Cr and O are 5 there fore the hybridisation is sp3d
note sigma bond are the primary bonds so whereever you see double bond then there are one sigma and one pi bonds
for lone pair take NH3 nitrogen has 1 lone pair and 3 σ bonds thus the hybridisation is sp3
```
6 years ago
```										can u please tell me how to find out the hybridisation for ph3 please and aso give me the explanation thank you
```
3 years ago
```										Just count the no.of sigma bonds and lone pairs (if any) Thats all!
```
2 years ago
```										What is the hybridization of I 3 minus?
```
2 years ago
```										for any compound identify the central atom then count the no. of sigma bonds and no. of lone pairs on it and then add them. eg: in a CO2 molecule carbon is the central atom, no. of sigma bonds are 2 and no. of lone pairs are 0 then sum is 2 which means sp hybridization is there.
```
2 years ago
```										for a shortcut. find the no of atoms attached to it. then write its corresponding hybridisation. if central atom is attached to 2.. sp.. 3..sp2.. so on
```
2 years ago
```										Countcount the no. Of sigma bond and no of lone of atom whose hybridisation is to be predicted . All single bonds ate sigma , in amultiple bond one will sigma others be pie
```
2 years ago
```										Accr to VSEPR theory H={V+M-C+A} the simplest method V = valence electrons in central atomM=number of univalent atom attached to central atomC=charge on cationA=charge on anion
```
2 years ago
```										dont,t get confused just no. of sigma bond + lone pairs ,if sum is 2--sp 3--sp2 4--sp3 5--sp3d 6--sp3d2 7--sp3d3
```
2 years ago
```										but what if remainder is not zero. it wont be divisible by 2 ex. CH3
```
one year ago
```										hybridization of h3po3
```
one year ago
```										calculate no. of bond pairs[sigma bonds only] and lone pairs and add them..the no. u get is the hybridisation of that atom...if h=2=sp,,if h=3=sp2,,if h=4=sp3,,if h=5=sp3d and so on
```
one year ago

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