Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
PRADEEP kumar TRIPATHI Grade: 12
        how to find hybridisation?i want shortcut or any trick
6 years ago

Answers : (16)

AKASH GOYAL AskiitiansExpert-IITD
419 Points

Dear Pradeep

Following is the way to find hybridisation

1st step    :  count the no. of valence electrons[ V ]
2nd step   :   now divide V by 8 ,if V >8
                    divide V by 2 ,if  V <=8                                   -[1]
                    if the remainder is still  not zero then
                   again divide it by 2,                                         - [2]
                   therefore the final value = quotient in 1+ quotient in 2
                  as    shown in the example
3rd step    :  compare the above obtained value with the table given below :-
                   sp          -   2
                   sp2        -   3
                   sp3        -   4
                   sp3d      -   5
                   sp3d2    -   6
                   sp3d3    -   7
ex:- for  c2h6
step  1   -   2[4 ] + 6[1] = 4+6=10
step  2    -   as 14>8 
                   14/8, quotient=1  as remainder  = 6 which is not equal to zero
                    therefore 6 / 2   quotient=3
                  therefore final value=1+3=4
                   comparing with the table given above
                   the hybridisation is sp3.
note -  this is not applicable  to all compounds

All the best


Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.

Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

6 years ago
vikas askiitian expert
510 Points

you can use HON rule

 according to this 2X=number of electrons in valence shell-charge+number of monovalent atoms attached(Cl,H etc)

  if x comes 2 then hybridisation is sp

  if 3 then sp2 ,if 4 then sp3 and so on

 example ..hybridisation of NH4+


            x=4 so hybridisation is sp3

 approve my ans if u like

6 years ago
Devasish Bindani
45 Points

to find the hybridisation of an element in a given compound  first count the number of σ bonds and the no. of lone pairs present then it becomes the steric no of the element then just get the hybridisation. hybridisation forsteric no.







thats it the short cut count the no of σ bonds  and ya got the hybridisation

note:- its applicable to all compounds provided ya know the structure or no of atoms connected to the given atom whose hybridisation is to be found hers an example check out


here no of σ bettween Cr and O are 5 there fore the hybridisation is sp3d

note sigma bond are the primary bonds so whereever you see double bond then there are one sigma and one pi bonds

for lone pair take NH3 nitrogen has 1 lone pair and 3 σ bonds thus the hybridisation is sp3

6 years ago
aishwarya aishu
18 Points

can u please tell me how to find out the hybridisation for ph3 please and aso give me the explanation thank you

4 years ago
Rahul John Joseph
31 Points
										Just count the no.of sigma bonds and lone pairs (if any) Thats all!
3 years ago
siddharth singhal
19 Points
										What is the hybridization of I 3 minus?
3 years ago
saksham agrawal
14 Points
										for any compound identify the central atom then count the no. of sigma bonds and no. of lone pairs on it and then add them. eg: in a CO2 molecule carbon is the central atom, no. of sigma bonds are 2 and no. of lone pairs are 0 then sum is 2 which means sp hybridization is there.
3 years ago
Aazim Bill SE Yaswant
20 Points
										for a shortcut. find the no of atoms attached to it. then write its corresponding hybridisation. if central atom is attached to 2.. sp.. 3..sp2.. so on
3 years ago
Parveen Khurana
31 Points
										Countcount the no. Of sigma bond and no of lone of atom whose hybridisation is to be predicted . All single bonds ate sigma , in amultiple bond one will sigma others be pie
3 years ago
34 Points
										Accr to VSEPR theory H={V+M-C+A} the simplest method 
V = valence electrons in central atom
M=number of univalent atom attached to central atom
C=charge on cation
A=charge on anion
3 years ago
14 Points
dont,t get confused just no. of sigma bond + lone pairs ,if sum is












2 years ago
Yashwardhan Bahure
24 Points
but what if remainder is not zero. it wont be divisible by 2 ex. CH3
one year ago
15 Points
hybridization of h3po3
one year ago
soliha noor
53 Points
calculate no. of bond pairs[sigma bonds only] and lone pairs and add them..the no. u get is the hybridisation of that atom...if h=2=sp,,if h=3=sp2,,if h=4=sp3,,if h=5=sp3d and so on
one year ago
Nike Puma
24 Points
										I hav a formula for finding hybridisationI call it "Magic Number"So......Magic Number = Number of connections   +1/2 ( Group no. of central atom   -         Valency of central atom   ±          Charge on molecule)**# Note that -ve charge is added      and +ve charge is subtractedAlso that this doesn`t apply for complexesSo group 13    group 4Now compare the magic no. with2--sp3--sp24--sp35--sp3d6--sp3d27--sp3d3 Eg.)   For    H3O+Magic Number = 3 + 1/2( 6 - 3 - 1 )                           =  3 + 1/2( 2 )                           =  3 + 1                           =  4Now 4 corresponds to sp3 hybridHence H3O+ is sp3 hybridised  group 3     group  14  
9 days ago
Ashish Nayakidi
36 Points
You can calculate accordingly as
V=valency of the central metal atom
M=no. of monovalent atoms attached to the central metal atom
C=charge on cation
A=charge on anion
8 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off
Get extra R 520 off

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details