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the relationship between osmotic pressurev at 273 K when 10 g glucose (P1),10g urea(P2) and 10 sucrose(P3) are dissolved in 250 ml of water: (A)P1>P2>P3 (B)P3>P2>P1(C) P2>P1>P3(D)P2>P3>P1;EXPLAIN IT

the relationship between osmotic pressurev at 273 K when 10 g  glucose (P1),10g urea(P2) and  10 sucrose(P3) are dissolved in 250 ml of water:


(A)P1>P2>P3 (B)P3>P2>P1(C) P2>P1>P3(D)P2>P3>P1;EXPLAIN IT

Grade:

3 Answers

suryakanth AskiitiansExpert-IITB
105 Points
13 years ago

Dear bharat,

The osmatic pressure is given by

Π = iMRT,

where

i is the dimensionless van 't Hoff factor
M is the molarity
R=0.08206 L · atm · mol-1 · K-1 is the gas constant
T is the thermodynamic (absolute) temperature


the osmatic pressure is directly proportional to the Molarity,since other values are constant for the three compounds.
The molarity is inversly proportional to Molecular weight.
Molecular weight of
Urea = 60
Glucose = 180
sucrose = 342

Hence our answer is
(C) P2>P1>P3

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vikas askiitian expert
509 Points
13 years ago

  P=CRT

osmotic pressure is inversly proportional to molar mass if all other parameteres are constant so higher will be the molar mass lower will be the osmotic pressure

 hence option c is correct

Rishi Sharma
askIITians Faculty 646 Points
3 years ago
Dear Student,
Please find below the solution to your problem.

The osmatic pressure is given by
Π = iMRT,
where
i is the dimensionless van 't Hoff factor
M is the molarity
R=0.08206 L · atm · mol-1 · K-1 is the gas constant
T is the thermodynamic (absolute) temperature
The osmatic pressure is directly proportional to the Molarity,since other values are constant for the three compounds.
The molarity is inversly proportional to Molecular weight.
Molecular weight of
Urea = 60
Glucose = 180
sucrose = 342
Hence our answer is
(C) P2>P1>P3

Thanks and Regards

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