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        assume that the potential energy of a hydrogen atom in its ground state is zero . then its energy in the first excited state will be
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
										Dear vikas,
$r_n = {n^2\hbar^2\over Zk_e e^2 m_e}$ The smallest possible value of r is called the Bohr radius and is equal to: $r_1 = {\hbar^2 \over (k_e e^2) m_e} = 0.529 \times 10^{-10} \mathrm{m}$  The energy of the n-th level is determined by the radius: $E = -{k_e e^2 \over 2r_n } = - { (k_e e^2)^2 m_e \over 2\hbar^2 n^2} = {-13.6 \mathrm{eV} \over n^2}$

We are all  IITians and here to help you in your IIT  JEE preparation.  All the best.
Sagar Singh
B.Tech IIT Delhi


6 years ago
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