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```        Please help me solve this problem:
a vessel of volume 100ml contains 10 % oxygen and 90% of an unknown gas.
The gases diffuse in 86 sec through a small hole of the vessel. If pure oxygen under the same conditions diffuses in 75 sec,. find the molecular weight of the gas .
Thank you,```
7 years ago

68 Points
```										Dear Rakshit ,
Graham's law of diffusiuon says -- the rate of diffusion of a gas is inversely proportional to the square root of it’s density or molecular weights. If r1 and r2 are the rates of diffusion of two gases, whose densities under the given conditions are d1 and d2 respectively, then we have

where M2and M1 are the molecular weights of the gases.
NOW , here molecular weight of oxygen  =  32
Let the molecular weight of gas be M , average molecular weight of gas mixture  =  (10*32 + 90 *M) /100 = 3.2 + .9 * M
Applying above law ,
roxygen / rmixture  =   (Mmixture /Moxygen)1/2
86/75 =( 3.2+ .9 *M / 32)1/2
solving we get = 43.19 gm

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7 years ago
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