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For a p-electron, orbital angular moment is
(A) √2h (B) h
(C) √6h (D) 2h plz EXPLAIN IT PROPER....
O.A.M= SQRT[ l*(l+1)] * h
FOR P ELECTRON L VALUE IS 1.
THEREFORE O.A.M= SQRT(2) * h
THEREFORE OPTION---A
orbital angular momentum of an orbital is given by {l(l+1)}1/2 h
for p orbital, l=1 (s=0
p=1
d=2
f=3)
o angular momentum= {1(1+1)}1/2 h ={1*2}1/2 h = 21/2 h
so the answer is A under root pf 2 multiplied by h
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