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				   to find no total no. of atom, if atom present on corner ,body centre, face centre , edge centre and two atoms on each body diagonal

6 years ago


Answers : (1)


Dear student,



BCC has 8 atoms at the corners and one atom, within the body. Each corner atom makes 1/8 contribution and the contribution of atom within the body = 1


 No of atoms present in bcc = 1/8 × 8 (at corner) + 1(at the body centre)


                                           = 1+1 =2




Fcc has 8 atoms at the corners and 6 atoms on the faces (one on each face)


Contribution by atoms at the corners = 1/8 × = 1


Contribution by atom on the face = 1/2 × 6 = 3


 Number of atoms present in fcc unit cell = 1+3 = 4


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