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Rahul Milind Surange Grade: 12
        

K.E. of the electron is . Its de Broglie wave length is

7 years ago

Answers : (1)

AskiitiansExpert Abhinav Batra
25 Points
										

Dear Rahul


we now from the de brogelie` law


p=h/λ


but p2/2m=K.E.


so p=√2mK.E.


so √2mK.E.=h/λ


hence λ=h/√2mK.E.=√(hπ/m) where m iS the maSS of electron


SubStituting the valueS h=6.626*10-34 m=9.1*10-31 π=22/7


λ=4.78*10-2 m



ALL THE best


AskIITIANsExpert


ABhinav Batra






7 years ago
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