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Ionisation potential and electron affinity of fluorine are 17.42 and 3.45 eV respectively. Calculate the electronegativeity of fluorine.

6 years ago


Answers : (1)


Dear Sakshi,

According to Mulliken equation:


        X = (I.P+E.A)/5.6  when both IP and EA are taken in eV.

        XF = (17.42+3.45)5.6  = 3.726

 Thus Electronegativity of Flourine is 3.726 provides online iit jee courses and IIT JEE Test Series with IITians. Click here to get free online test series and check your status timely or you can join us as our registered user for getting best iit jee study material or iit jee test series.

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Akhilesh Shukla

6 years ago

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