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Nehal Wani Grade:
        


If the dissociation constant of HCN is 4.8 X 10-10 mol dm-3, then the pH of 0.25 mol dm-3 NaCN solution is



7 years ago

Answers : (1)

Askiitians Expert Sahil Arora - IITD
19 Points
										

Dear Nehal


As NaCN is a salt of strong base and weak acid


So pH =  1/2pKw +  1/2pKa +  1/2log C


= 7 + 1/2pKa +  1/2log C.


 


 


 


 









Put Ka=4.8 X 10-10 mol dm-3 and C=0.25 mol/dm3.


we get pH=8.55


for more details read:-


http://www.askiitians.com/iit-jee-chemistry/physical-chemistry/salt-of-weak-acid-and-strong-base.aspx


Please feel free to post as many doubts on our discussion forum as you can. If you find any question 
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All the best Nehal !!!




Regards,

Askiitians Experts

Sahil Arora

 



 

7 years ago
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