0

Guest

Courses New

1.The emf of a daniel cell at 298K is E1. Zn/ZnSO4(0.001M)||CuSO4(1.0M)/Cu.when the conc of ZnSO4 is 1M and that of CuSO4 is 0.01Mthe emf changed to E2.What is the relationship between E1 and E2 2.Given E(Fe3+/Fe)= -0.036V , E(Fe2+/Fe)= -0.439V the value of standard electrode potential for the change Fe3+ + e- giving Fe2+ will be

1.The emf of a daniel cell at 298K is E1.
Zn/ZnSO4(0.001M)||CuSO4(1.0M)/Cu.when the conc of ZnSO4 is 1M and that of CuSO4 is 0.01Mthe emf changed to E2.What is the relationship between E1 and E2
2.Given E(Fe3+/Fe)= -0.036V ,
E(Fe2+/Fe)= -0.439V
the value of standard electrode potential for the change Fe3+ + e- giving Fe2+ will be 

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
  1. For E1 = Eocell – (0.0529/2)log(Zn2+/Cu2+) => Eocell – (1.5)(0.0529)........(1)
For E2 = Eocell – (0.059)..............(2)
Substract the eqns. (1) and (2) we get,
E1 – E2 = 0.059*2.5 = > 0.13225 VOLT
 
  1. Fe3+ + 3e- ==>    Fe
and
Fe2+ + 2e- ===> Fe
Now reversing the second reaction and addiing with the first, we get the relation as:
E1 – E2 = Ecell for  Fe3+ + e- giving Fe2+.

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More