Guest

(1) A bulb of 40 W is producing a light with 80% efficiency. Then the number of photons emitted in 20 seconds are (1eV = 1.6 X 10 -19 J, hc = 12400 eV A o ) ​ :- ​(a) 2 X 10 18 (b) 10 18 (c) 10 21 (d) 2 X 10 21 ​ (2) In a certain electronic transition in the Hydrogen atom from an initial state (1) to a final state (2), the difference in the orbital radius (r 1 - r 2 ) is 24 times the first Bohr radius. The transition is :- (a) 5 to 1 (b) 25 to 1 (c) 8 to 3 (d) 6 to 5

(1) A bulb of 40 W is producing a light with 80% efficiency. Then the number of photons emitted in 20 seconds are (1eV = 1.6 X 10-19 J, hc = 12400 eV Ao)​ :-
​(a) 2 X 1018                          (b) 1018
(c) 1021                          (d) 2 X 1021
 
(2) In a certain electronic transition in the Hydrogen atom from an initial state (1) to a final state (2), the difference in the orbital radius (r1 - r2) is 24 times the first Bohr radius. The transition is :-
(a) 5 to 1                         (b) 25 to 1
(c) 8 to 3                         (d) 6 to 5
 

Grade:10

1 Answers

akashdeep mitra
37 Points
9 years ago
answer to the first question is 1018 photons and to the second is 5 to 1.

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free