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(1) A bulb of 40 W is producing a light of wavelength 620 nm with 80% efficiency. Then the number of photons emitted in 20 seconds are (1eV = 1.6 X 10 -19 J, hc = 12400 eV A o ) ​ :- ​(a) 2 X 10 18 (b) 10 18 (c) 10 21 (d) 2 X 10 21 ​

 
(1) A bulb of 40 W is producing a light of wavelength 620 nm with 80% efficiency. Then the number of photons emitted in 20 seconds are (1eV = 1.6 X 10-19 J, hc = 12400 eV Ao)​ :-
​(a) 2 X 1018                          (b) 1018
(c) 1021                          (d) 2 X 1021​
 

Grade:10

1 Answers

Saurabh Kumar
askIITians Faculty 2400 Points
9 years ago
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