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1.520g of hydroxide of metal on ignition gave 0.995g of oxide. The equivalent weight of metal is

1.520g of hydroxide of metal on ignition gave 0.995g of oxide. The equivalent weight of metal is

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Grade:12th pass

3 Answers

Nakshatra
30 Points
6 years ago
Let equivant wt of metal be E now using cobination method and equating the gram equivalents (gmeqs):1.520/E+17 = 0.995/E+80.525E = 4.755E=9.05
Shruti chaturvedi
11 Points
6 years ago
One equivalent of the metal reacts with one mole of OH ,i.e, 17 grams.Similarly,one equivalent of the metal reacts with 1/2 moles of oxygen atoms ,i.e, 8grams of oxygen atoms.Let E be the equivalent mass of the metal.And let X be the no. of equivalents of metal hydroxide ignited.Therefore, x[E+17] = 1.520 grams & x[E+8] = 0.995 gramsBy eliminating x , we get E= 9.06 grams..
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the solution to your problem.
 
One equivalent of the metal reacts with one mole of OH ,i.e, 17 grams.
Similarly,one equivalent of the metal reacts with 1/2 moles of oxygen atoms ,i.e, 8grams of oxygen atoms.
Let E be the equivalent mass of the metal.And let X be the no. of equivalents of metal hydroxide ignited.
Therefore, x[E+17] = 1.520 grams & x[E+8] = 0.995 grams
By eliminating x , we get E= 9.06 grams..
 
Thanks and regards,
Kushagra

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