0.5 mole BaCl2 is mixed with 0.2 mole Na3PO4 , find the maximum no. of moles ofBa3(PO4)3 that can be formed

Question

Vikas TU · Answer

Dear Student,
The reaction is:

3 BaCl2 + 2 Na3PO4 = Ba3(PO4)2 + 6NaCl
So from the mole – 1 analysis,
Here clearly BaCl2 is the limiting agent
So 3 moles of bacl2 gives 1 mole of ba3(po4)2
so 0.5 mole will give 0.2 mole(approx).

HENCE 0.2 MOLES is the answer.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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0.5 mole BaCl2 is mixed with 0.2 mole Na3PO4 , find the maximum no. of moles ofBa3(PO4)3 that can be formed

0.5 mole BaCl2 is mixed with 0.2 mole Na3PO4 , find the maximum no. of moles ofBa3(PO4)3 that can be formed

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0.5 mole BaCl2 is mixed with 0.2 mole Na3PO4 , find the maximum no. of moles ofBa3(PO4)3 that can be formed

0.5 mole BaCl2 is mixed with 0.2 mole Na3PO4 , find the maximum no. of moles ofBa3(PO4)3 that can be formed

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