Why only the -OH group from 5th carbon(not -OH group from any other carbon)attacks on 1st carbon of glucose during the formation of cyclic anomers?

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Vikas TU · Answer

Already Answered: Again Reposting: To reduce the steric hindrances and bulkiness and to gain the more stablity with more number of carbon chains It choose the 5 th carbon atom to get eliminated. Reasons are same: To achieve the stability level.

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Why only the -OH group from 5th carbon(not -OH group from any other carbon)attacks on 1st carbon of glucose during the formation of cyclic anomers?

Why only the -OH group from 5th carbon(not -OH group from any other carbon)attacks on 1st carbon of glucose during the formation of cyclic anomers?

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Why only the -OH group from 5th carbon(not -OH group from any other carbon)attacks on 1st carbon of glucose during the formation of cyclic anomers?

Why only the -OH group from 5th carbon(not -OH group from any other carbon)attacks on 1st carbon of glucose during the formation of cyclic anomers?

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