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Why does only HBr give anti-Markownikoff product in presence of peroxide among all halo acids?

Why does only HBr give anti-Markownikoff product in presence of peroxide among all halo acids?

Grade:12th pass

4 Answers

Vikas TU
14149 Points
7 years ago
Because perocide gives the power to the HBr to get added in “wrong way around” which is therfore know as peroxide effect. And in absence or H2O2 it reacts with the mechanism following the Markownikov’rs  simple electrophilic addition rule. 
pragati dound
21 Points
7 years ago
In markovinkow rulr the electrophile was H+ion (in absence of peraoxide)but in antimarkovinkow rule the electrophile is Bromine free radical(in presence of peraoxide) this happens only with HBrnot wit HClor HI becaise there bond are much stronger than HBr and hence there is no effect of peraoxide on themand therefor there electrophile will be H+only not iodene free radical or Cl free radical
pragati dound
21 Points
7 years ago
In markovinkow rulr the electrophile was H+ion (in absence of peraoxide)but in antimarkovinkow rule the electrophile is Bromine free radical(in presence of peraoxide) this happens only with HBrnot wit HClor HI becaise there bond are much stronger than HBr and hence there is no effect of peraoxide on themand therefor there electrophile will be H+only not iodene free radical or Cl free radical therefore they follow normal markovinkw rule
Shikhar
13 Points
5 years ago
HF and HCl have high bond strength and polarity , so homolytic cleavage does not occur easily. In HBr and HI homolytic cleavage occurs readily to produce bromine and iodine free radicals .however iodine radical undergoes coupling reaction
I• + l • gives l2 
As a result iodine radicals arenot available for addition on alkene .Thus, only HBr can provide free radicals .Hence The Peroxide effect is observed only in case of HBr. 

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