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when a solution of propanoic acid is half neutralized with NaOH,then ph equals to 4.87.what is the dissociation constant of acid

when a solution of propanoic acid is half neutralized with NaOH,then ph equals to 4.87.what is the dissociation constant of acid

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
As of now Answered this qstn. 
Plz do check your prevvious one! 
Half of propanoic corrosive gets killed. 
Henceforth for a mol of propanoic corrosive a/2 mol left. 
4.87 = - log[H+] 
- log((ka * CH3 – CH2 – COOH)/(CH3COO-)) = 4.87 
On unraveling we get, 
Ka = 10^-4.87/2.

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