I want answer for NaO-COO-CH 2 -CH 2 -CH 2 -CH 2 -CH2-COO-O-Na gives rise to on excess soda lime by heating......................................................by decarboxylation

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Vikas TU · Answer

First use the NaOH and heat it with together soda lime. that is CaO. OH- attacks on the -COOH and -COO- group and form R-COOOH— ion.

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I want answer for NaO-COO-CH 2 -CH 2 -CH 2 -CH 2 -CH2-COO-O-Na gives rise to on excess soda lime by heating......................................................by decarboxylation

I want answer for NaO-COO-CH₂-CH₂-CH₂-CH₂-CH2-COO-O-Na gives rise to on excess soda lime by heating......................................................by decarboxylation

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I want answer for NaO-COO-CH 2 -CH 2 -CH 2 -CH 2 -CH2-COO-O-Na gives rise to on excess soda lime by heating......................................................by decarboxylation

I want answer for NaO-COO-CH2-CH2-CH2-CH2-CH2-COO-O-Na gives rise to on excess soda lime by heating......................................................by decarboxylation

1 Answers

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I want answer for NaO-COO-CH₂-CH₂-CH₂-CH₂-CH2-COO-O-Na gives rise to on excess soda lime by heating......................................................by decarboxylation