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```				   A compound of carbon,hydrogen and nitrogen contains the elements in the ratio of 18:2:7.Its empirical formula will be
```

7 years ago

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### Answers : (2)

```										Let the compound be CaHbNc
and stomic wts. are 12,1,14 respectiveky for C,H,N
12a/(12a+b+14c) = 18/27   ... (1)
b/(12a+b+14c) = 2/27        ... (2)
14c/(12a+b+14c) = 14/27   ... (3)
on dividing 1 and 3 , we have ... a = 3c
on dividing 2 and 3 , we have ... b = 4c
so, the empirical formula is C3H4N
--
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.Regards,Ramesh   IIT Kgp - 05 batch

```
7 years ago
```										hi,

elements

ratio

P  =ratio/corresponding atomic wt

P divided by least no. in previous column

Ratio of atoms in empirical formula

C

18

18/12 = 1.5

1.5/0.5 =3

3

H

2

2/1 = 2

2/ 0.5 = 4

4

N

7

7 / 14 = 0.5

.5 /.5 = 1

1

so , empirical formula of compound would be =
= C3 H4 N
```
7 years ago

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