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pallavi pradeep bhardwaj Grade: 12
        

A compound of carbon,hydrogen and nitrogen contains the elements in the ratio of 18:2:7.Its empirical formula will be

7 years ago

Answers : (2)

Ramesh V
70 Points
										

Let the compound be CaHbNc


and stomic wts. are 12,1,14 respectiveky for C,H,N


12a/(12a+b+14c) = 18/27   ... (1)


b/(12a+b+14c) = 2/27        ... (2)


14c/(12a+b+14c) = 14/27   ... (3)


on dividing 1 and 3 , we have ... a = 3c


on dividing 2 and 3 , we have ... b = 4c


so, the empirical formula is C3H4N


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IIT Kgp - 05 batch






7 years ago
Pratham Ashish
17 Points
										

hi,



































elements



ratio



P  =ratio/corresponding atomic wt



P divided by least no. in previous column



Ratio of atoms in empirical formula



C



18



18/12 = 1.5



1.5/0.5 =3



3



H



2



2/1 = 2



2/ 0.5 = 4



4



N



7



7 / 14 = 0.5



.5 /.5 = 1



1




  so , empirical formula of compound would be =


                                                                 = C3 H4 N

7 years ago
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