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tanA +tanB+ tanC +tanD=tanAtanBtanCtanD(cotA+cotB+cotC+cotD) prove this expression if A+B+C+D=2pi

tanA +tanB+ tanC +tanD=tanAtanBtanCtanD(cotA+cotB+cotC+cotD) prove this expression if A+B+C+D=2pi

Grade:12th pass

1 Answers

Ankit yadav
26 Points
6 years ago
Since about angle`s a,b,c,d nothing is given so we can let anything a,b,c,d which is equal to 2π, so let a=60°, b=30°,c=150°,d=120. a+b+c+d=2πNow put the value of angels in both L.H.S and R.H.S which will be equal to 0. So hence proved

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