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How many 8 digit numbers can be formed using two 1's, two 2's, two 3's, 4 and 5 so that no two consecutive digit is identical.....

How many 8 digit numbers can be formed using two 1's, two 2's, two 3's, 4 and 5 so that no two consecutive digit is identical.....

Grade:11

1 Answers

umesh
19 Points
7 years ago
first take all things only one like 1,2,3,4,5 and arrange them in 5! ways and now take an exanple 1   2   3   4   5 and 1,2,3 will be left
and we observe that number of ways of arrange any one of them is 4 and after arranging this aranging other is 5 ways and another is 6 ways so answer is 5!*4*5*6

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