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`        When a metal plate is exposed to a monochromatic beam of light of wavelength 400 nm, a negative potential of 1.1 V is needed to stop the photocurrent. Find the threshold wavelength for the metal.`
3 years ago

Navjyot Kalra
654 Points
```										Sol. λ = 400 nm = 400 * 10^-9 m
V base 0 = 1.1 V
hc/λ = hc/λ base 0 + ev base 0
⇒ 6.63 * 10^-34 *3 * 10^8/400 * 10^-9 = 6.63 * 10^-34 *3 * 10^8/λ base 0
⇒ 4.97 = 19.89 * 10^-26/λ base 0 + 1.76
⇒ 19.89 * 10^-26/λ base 0 = 4.97 – 17.6 = 3.21
⇒ λ base 0 = 19.89 * 10^-26/3.21 = 6.196 * 10^-7 m = 620 nm.

```
3 years ago
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