Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Shane Macguire Grade: upto college level
`        What potential difference should be applied across an X-ray tube to get X-ray of wavelength not less than 0.10 nm? What is the maximum energy of a photon of this X-ray in joule?`
3 years ago

## Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
```										λ = 0.10 nm = 10^10 m ; h = 6.63 * 10^34 J-s
C = 3 * 10^8 m/s ; e = 1.6 * 10^19 C
λ base min = hc/eV or V = hc/eλ
= 6.63 *10^-34 * 3 * 10^8/1.6 *10^-19 *10^-10 = 12.43 *10^3 V = 12.4 KV.
Max. Energy = hc/λ = 6.63* 10^-34 *3* 10^8/10^10 = 19.89 * 10^-18 = 1.989 * 10^-15 =2 * 10^-15 J.

```
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Modern Physics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 413 off
USE CODE: COUPON10
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 445 off
USE CODE: COUPON10

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details