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Shane Macguire Grade: upto college level
`        Visible light has wavelengths in the range of 400 nm to 780 nm. Calculate the range of energy of the photons of visible light.`
3 years ago

Navjyot Kalra
654 Points
```										Sol. λ base 1 = 400 nm to λ base 2 = 780 nm
E = hv = hc/λ h = 6.63 * 10^-34 j – s, c = 3 * 10^8 m/s, λ base 1 = 400 nm, λ base 2 = 780 nm
E base 1 = 6.63 * 10^-34 * 3 * 10^8/400 * 10^-9 = 6.63 *3/4 * 10^-19 = 5 * 10^-19 J.
E base 2 = 6.63 *3/47.8 * 10^-19 = 2.55 * 10^-19 J
So, the range is 5 * 10^-19 J to 2.25 * 10^-19 J.

```
3 years ago
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