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Simran Bhatia Grade: 11
         The electric field associated with a monochromatic beam becomes zero 1.2 × 10^15 times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV. 
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. The electric field becomes 0 1.2 * 10^45 times per second.

∴ Frequency = 1.2 * 10^15/2 = 0.6 * 10^15
hv = ∅ base 0 + KE
⇒ hv - ∅ base 0 = KE
⇒ KE = 6.63 * 106-34 *0.6 * 10^15/1.6 * 10^-19 – 2
= 0.482 ev = 0.48 ev.
3 years ago
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