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A radioactive for the substance has 10^8 nuclei
k=0.693/t1/2
t1/2= half life (Its half life is 30s)
k=disintegration or rot consistent 0.693/30 = k
k=0.0231
k=2.303log(a/a-x)/t
a=initial sum
a-x= sum left after deterioration
t=time of rot
0.0231=2.303log(108/108-x)/15
108/108-x=1.41
Amount left=108-x=7,09,21,986 nuclei.
Therefore The no, of nuclei left after 15s is nearly = 7,09,21,986 nuclei
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