Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A photographic film is coated with a silver bromide layer. When light falls on this film, silver bromide molecules dissociate and the film records the light there. A minimum of 0.6 eV is needed to dissociate a silver bromide molecule. Find the maximum wavelength of light that can be recorded by the film.`
3 years ago

Navjyot Kalra
654 Points
```										Sol. w base 0 = 0.6 ev
For w0 to be min ‘λ’ becomes maximum.
W base 0 = hc/λ or λ = hc/w base 0 = 6.63 * 10^-34 *3 * 10^8/0.6 * 1.6 * 10^-19
= 20.71 * 10^-7 m = 2071 nm

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Modern Physics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 413 off
USE CODE: COUPON10
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 445 off
USE CODE: COUPON10