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Amit Saxena Grade: upto college level
        A horizontal cesium plate (φ = 1.9 eV) is moved vertically downward at a constant speed v in a room full of radiation of wavelength 250 nm and above. What should be the minimum value of v so that the vertically upward component of velocity is non-positive for each photoelectron?
3 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
										Sol. When λ  = 250 nm

Energy of photon = hc/λ = 1240/250 = 4.96 ev
∴ K.E. – hc/λ = 1240/250 = 4.96 ev
Velocity to be non positive for each photo electron
The minimum value of velocity of plate should be = velocity of photo electron
∴ Velocity of photo electron = √2Ke/m
= √3.06/9.1 * 10^-31 = √3.06 * 1.6 * 10^-19/9.1 * 10^-31 = 1.04 * 10^6 m/sec.
3 years ago
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