40 N
A displacement vector of magnitude 12m is making
angle of +120 0 with +X axis.The x & y components of
the vector are
[B]
A) +6m and
√ 3 m
C) -6m & 6 √ 3 m
6)
B) -6m & -6
√ 3 m
D) 6m & -6 √ 3 m

Question

Vikas TU · Answer

Components in x and y directions respectively are: In x – direction, => 12cos60 = > -6i meter. In y- direction, => 12sin60 => 6root(3)j meter i and j caps are the -ve x and positive y directions respectively.

utpal raj · Answer

basically you can take any angle from vector , you need to do components of vector , take the cos(theta) in which you have taken angle and other as sin (theta) and multiply with vector length , do components,

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40 N A displacement vector of magnitude 12m is making angle of +120 0 with +X axis.The x & y components of the vector are [B] A) +6m and √ 3 m C) -6m & 6 √ 3 m 6) B) -6m & -6 √ 3 m D) 6m & -6 √ 3 m

40 N
A displacement vector of magnitude 12m is making
angle of +120 0 with +X axis.The x & y components of
the vector are
[B]
A) +6m and
√ 3 m
C) -6m & 6 √ 3 m
6)
B) -6m & -6
√ 3 m
D) 6m & -6 √ 3 m

2 Answers

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40 N A displacement vector of magnitude 12m is making angle of +120 0 with +X axis.The x & y components of the vector are [B] A) +6m and √ 3 m C) -6m & 6 √ 3 m 6) B) -6m & -6 √ 3 m D) 6m & -6 √ 3 m

40 NA displacement vector of magnitude 12m is makingangle of +120 0 with +X axis.The x & y components ofthe vector are[B]A) +6m and√ 3 mC) -6m & 6 √ 3 m6)B) -6m & -6√ 3 mD) 6m & -6 √ 3 m

2 Answers

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40 N
A displacement vector of magnitude 12m is making
angle of +120 0 with +X axis.The x & y components of
the vector are
[B]
A) +6m and
√ 3 m
C) -6m & 6 √ 3 m
6)
B) -6m & -6
√ 3 m
D) 6m & -6 √ 3 m