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Assume that two deuteron nuclei in the core of fusion reactor at temperature T are moving towards each other, each with kinetic energy 1.5 kT, when the separation between them is large enough to neglect Coulomb potential energy. Also neglect any interaction from other particles in the core. The minimum temperature T required for them to reach a separation of 4 × 10-15 m is in the range
Dear Ankita Shakya,
Ans:- The initial energy is totally linetic and the total energy is=2(1.5kT)=3kT and initially there is no coulombic P.E.
Then finally the total energy must be converted to the potential energy as the temp is minimum( assuming the final temp to be zero). Hece from energy equation we get
Kq²/r=initial KE
Solving we get,
T=(5.12×10^-14)/k(ans)
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Regards,
Askiitians ExpertsSoumyajit Das IIT Kharagpur
Dear STUDENT NAME,
In the previous solution the answer was wrong due to some calculation mistake please note the correct answer. The correct Temperature is T=(1.92×10^-14)/k Kelvin where k is a constant
All the best STUDENT NAME !!!
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