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				   A vessel containing water is kept on a weighing machine. The

machine registers a weight of 100 N. A wooden block having cubical
shape and edge length 10 cm is gently put in water. Water does not
spill out of the vessel. Now it observed that the weighing machine
registers a weight of 106 N. Calculate the depth to which the block
will submerge in water. Density of water is 1 g/cc.

6 years ago

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Answers : (1)

										

Dear Ajinkya Bhole,


Ans;- As it is clear from the problem that the weight of the block is (106-100) =6N=600 gm.


 it's vol is 10³=1000 cc


Hence the density is =600/1000=0.6 g/cc


Hence the fraction of the vol that will remain inside the water is =(0.6/1)=3/5.


So, the block will submerge upto a depth of 10×(3/5)=6 cm


 


  


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6 years ago

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