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rajan jha Grade: 12
        

An electron spends about 10^-8s in an excited state before it drops to a lower state by emiting a photon. How many revolution does an electron in an n=2 bohr orbit make in 1.00*10^-8s? (ans_8.23*10^6 revolution)

7 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

velocity in any orbit = (2.18*106)/n m/s


 V2 = (2.18*106)/2 m/s


radius of any orbit =  (52.9)*10-12n2 m


r2 = (52.9*10-12)4 m


time in which electron completes one revolution is


T = 2pir2/V2


T =12*10-16                    


let it completes n crevolution so total time taken = n(12*10-16)


 n(12*10-16) = 10-8


    n = 8.23 * 106 revolutions

7 years ago
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