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a bloack of mass under root 3kg is resting on a horizontal plane (coefficient of static friction =1/2under root3 ) . A foce is applied to the block at an angle of 60 . The minimum magnitude of force for which the block begins to slide is (g =10m/s square)      please explain

6 years ago


Answers : (1)


taking two components of force seperatly fcos@ and f sin@  

 fcos@ will become driving force and

  (mg-fsin@) will be the normal reaction acting on the body

  we know, friction force= u.normal reaction ,u=cofficient of friction

for minimum force fcos@=friction force 

    f=20/3 N


6 years ago

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