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`        An electron, an alpha particle, and a proton have the same kinetic energy.Which of these particles has the shortest, de-Broglie wavelength?`
7 years ago

21 Points
```										kinetic energy is given by E= (1/2)mv^2.Same kinetic energy means electron has highest vellocity( to make for its small mass)Assume mass of electron as 1 unit.mass of proton aprrox 1836 and mass of alpha particle is 4 times ie is 7344.now calculate velocity in each caseFor electron v= squareroot(2E)F0r proton v = squareroot(2E/1836)for alpha particle v=squareroot(2E/7344)Also de-Broglie wavelength is given by Lambda= h/mvNow calculate momentum in easch caseFor electron mv= squareroot(2E)*1For proton v = squareroot(2E/1836)*1836For alpha particle v=squareroot(2E/7344)*7344Clearly electron has least momentum. Hnece it has largest de-Broglie wavelength. And Alpha particle has least wavelength.
```
7 years ago
Sushmitha Naidu
18 Points
```										among alpha particle,electron,neutron and proton whch has highest wavelenght???
```
2 years ago
Anmol
13 Points
```										alpha particle has the highest wavelength
```
2 years ago
Mihir
69 Points
```										Kinetic Energy is realted to momentum asK= P2/2m, where m is the mass of the particle.Now, P= sqrt(2mK), which means the linear momentum is proportional to square root of mass. Hence, de Broglie wavelength is inversely prorprtional to the square root of mass. Therefore, the electron having the least mass shall possess maximum de Broglie wavelength.
```
2 years ago
Shubham Singh
199 Points
```										K= P2/2m the more the mass the more the momentumthe more the momentum , the less the wavelengthso mass is inversely  proportional to wavelength
```
2 years ago
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