Two bodies are thrown simultaneously from a tower with same initial velocity one vertically upward and the other vertical downward. The distance between the two bodies after time t is?

Question

Amarjit · Answer

Let the initial velocity be u.For upward:-S=ut-1/2(at²) is the displacement in upward direction.For the one thrown downward:-S=ut+1/2(at²).Hence now the distance b/w the two bodies after time t is = 2ut.

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Two bodies are thrown simultaneously from a tower with same initial velocity one vertically upward and the other vertical downward. The distance between the two bodies after time t is?

Two bodies are thrown simultaneously from a tower with same initial velocity one vertically upward and the other vertical downward. The distance between the two bodies after time t is?

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Two bodies are thrown simultaneously from a tower with same initial velocity one vertically upward and the other vertical downward. The distance between the two bodies after time t is?

Two bodies are thrown simultaneously from a tower with same initial velocity one vertically upward and the other vertical downward. The distance between the two bodies after time t is?

1 Answers

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