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Time period of particle executing SHM is 8 sec.At t=0 it is at the mean position. The ratio of distance covered by the particle in the 1^st second to the 2^ second

Time period of particle executing SHM is 8 sec.At t=0 it is at the mean position. The ratio of distance covered by the particle in the 1^st second to the 2^ second

Grade:12

1 Answers

Vikas TU
14149 Points
7 years ago
It would cover the amolitudes in 4 equal parts with Time Period T/4 and amplitude A/4.
Therefore, T/4 is 2 seconds.
And distance covered in 1st second would be => A/8 and and in 2nd second it would be = A/4
The ratio would be => (A/8)/(A/4) = > ½ => 1:2

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