the speed of a projectile at its maximum height is root3 /2 times its intial speed. if the range of the projectile is ‘p’ times the maximum height attained by it,then p=

Question

Vikas TU · Answer

Dear Student,

Speed at max ht=ucos=√(3/2) u
=>=30⁰

Range=u2sin2/g
=u2√3/20

height= u2sin2/2g
=u2/80
ATQ,
u2√3/20=p x u2/80
=>p=4√3

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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the speed of a projectile at its maximum height is root3 /2 times its intial speed. if the range of the projectile is ‘p’ times the maximum height attained by it,then p=

the speed of a projectile at its maximum height is root3 /2 times its intial speed. if the range of the projectile is ‘p’ times the maximum height attained by it,then p=

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the speed of a projectile at its maximum height is root3 /2 times its intial speed. if the range of the projectile is ‘p’ times the maximum height attained by it,then p=

the speed of a projectile at its maximum height is root3 /2 times its intial speed. if the range of the projectile is ‘p’ times the maximum height attained by it,then p=

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