six forces of magnitude 10,12,15,12.16 and 10KN are acting the sides of regular hexagon of side 2m .find its resultant force and ut’s directon

Question

Seema Arvind Khimavat · Answer

As forces are acting on sides of a regular hexagon we can find resultant of each force in x and y direction by knowing the angle each side makes with horizontal and we can find resultant as under root of (force in x)^2 +(force in y)^2.

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six forces of magnitude 10,12,15,12.16 and 10KN are acting the sides of regular hexagon of side 2m .find its resultant force and ut’s directon

six forces of magnitude 10,12,15,12.16 and 10KN are acting the sides of regular hexagon of side 2m .find its resultant force and ut’s directon

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six forces of magnitude 10,12,15,12.16 and 10KN are acting the sides of regular hexagon of side 2m .find its resultant force and ut’s directon

six forces of magnitude 10,12,15,12.16 and 10KN are acting the sides of regular hexagon of side 2m .find its resultant force and ut’s directon

1 Answers

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Other Related Questions on Mechanics

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