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Question attached in the image. ...Solution required please

Question attached in the image. ...Solution required please

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Grade:11

1 Answers

Mallikarjun Maram
50 Points
8 years ago
Given that, \bar{u} = 3\hat{i}\ m/s, \ \bar{F} = -2 \hat{i} N, \ \mu = 0.1 \and \ m = 4 kg. Friction force acting on the block is given by f = - \mu m g \hat {i} = - 0.1 * 4 * 10 \hat {i} = -4 \hat{i} N.  Hence net force is given by \bar {F} _{net} = - 6 \hat {i} N.  Acceleration of the block is then \bar a = - \frac{3}{2} \hat i \ m/sec^{2}.
Then from \bar v = \bar u + \bar a * t, you may find that at t = 2 sec.  velocity of the block is zero, and in 2 sec the block will have displacement of 3 \hat i m.  (from \bar s = \bar u t + \frac{1}{2} \bar a t ^{2}).
After 2 seconds, you can see that the block cannot move, as the applied force 2 N is less than the limiting friction of 4 N.  Hence total displacement after 5 sec is equal to 3 \bar im.

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