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​Q. A BODY IS MOVING IN A CIRCLE AT A UNIFORM VELOCITY v. THE MAGNITUDE OF CHANGE IN VELOCITY WHEN THE RADIUS VECTOR DESCRIBES AN ANGLE OF 60 0 IS- 4v v/2 v (3) 1/2 v/2

​Q. A BODY IS MOVING IN A CIRCLE AT A UNIFORM VELOCITY v. THE MAGNITUDE OF CHANGE IN VELOCITY WHEN THE RADIUS VECTOR DESCRIBES AN ANGLE OF 600 IS-
  1. 4v
  2. v/2
  3. v
  4. (3)1/2v/2

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3 Answers

Manabendra Nath Gaine
12 Points
9 years ago
v
Bharat Makkar
34 Points
9 years ago
but how? please give reason
shashi K Sharma
46 Points
9 years ago
The velocity vector is perpendicular to radius vector,LET v1 and v2 be the velocity vector(s) at the instant 1 and 2 respectively between which the angle described is 60degree
thus the angle between v2 vector and v1 vector is 60degree, the magnitude of each being v(as you said it is uniform circular motion)
thus the change is |v2 vector – v1 vector| =( v^2 +v^2 -2.v.v.Cos60)^.5 which is v

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