kindly help e in this question,a 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of 36km/h .if the coeffecient of kinetic frictin between the road and tyres is 0.2,calculate the power delivered by the engine (take g =10)

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Priya · Answer

Weight of truck, mg=10×1000×10N=100000NComponent of weight of truck down the incline,F=mgsina=10^5×1/50=2000NFrictional force=(mue) mg =0.2×10^5=20000NTotal force = 2000+20000=22000NPower=force×velocity=22000×10 =22×10^4N

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kindly help e in this question,a 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of 36km/h .if the coeffecient of kinetic frictin between the road and tyres is 0.2,calculate the power delivered by the engine (take g =10)

kindly help e in this question,a 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of 36km/h .if the coeffecient of kinetic frictin between the road and tyres is 0.2,calculate the power delivered by the engine (take g =10)

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kindly help e in this question,a 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of 36km/h .if the coeffecient of kinetic frictin between the road and tyres is 0.2,calculate the power delivered by the engine (take g =10)

kindly help e in this question,a 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of 36km/h .if the coeffecient of kinetic frictin between the road and tyres is 0.2,calculate the power delivered by the engine (take g =10)

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