Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Let ai+bj and ci+dj be the unit vectors.From the defination,√a2+b2=1⇒(a2+b2)=1___(1)√c2+d2=1⇒(c2+d2)=1____(2)
Add the above two vectors,(ai+bj)+(ci+dj) =(a+c)i+(b+d)j__(3)
Also given that,The magnitude of equation(3) is also unity.√(a+c)2+(b+d)2=1⇒((a+c)2+(b+d)2)=1⇒(a2+c2+2ac)+(b2+d2+2bd)=1⇒1+2ac+1+2bd=1⇒1+2ac+2bd+1=1⇒ac+bd=−12___(4)the magnitude of their difference is:?THe difference of two unit vectors is (ai+bj)−(ci+dj)=(a−c)i+(b−d)jMagnitude=√(a−c)2+(b−d)2=√a2+c2−2ac+b2+d2−2bd=√1+1−2(ac+bd) [From (1) and (2)]=√2−2(−12) [From equation(4)
=√2+1=√3=1.73205
let two vectors are a,b then
resultant of sum = (a2 + b2 + 2abcos@)1/2 = 1 (given)
a = b = 1 (unit vector)
1+1+2cos@ = 1
cos@ = -1/2 .................1
now resultant of difference = magnitude (a-b)
R = (a2 + b2 - 2abcos@)1/2
a = b = 1 , cos@ = -1/2 so
R = [ 1+1+1]1/2 = root3
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !