how long will it take for a wooden block of mass 2kg to from rest a distance of 3m down a rough plane inclined at 30 degree to the horizontal?given coefficient of sliding friction=0.20

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Anvita Bajpai · Answer

u=0, s=3 applying s=ut+1/2at 2 since u=0, the formula reduces to, s=1/2 at 2 where a=gsin 30 . -u k mgcos 30 t=(2s/a) 1/2

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how long will it take for a wooden block of mass 2kg to from rest a distance of 3m down a rough plane inclined at 30 degree to the horizontal?given coefficient of sliding friction=0.20

how long will it take for a wooden block of mass 2kg to from rest a distance of 3m down a rough plane inclined at 30 degree to the horizontal?given coefficient of sliding friction=0.20

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how long will it take for a wooden block of mass 2kg to from rest a distance of 3m down a rough plane inclined at 30 degree to the horizontal?given coefficient of sliding friction=0.20

how long will it take for a wooden block of mass 2kg to from rest a distance of 3m down a rough plane inclined at 30 degree to the horizontal?given coefficient of sliding friction=0.20

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