0

Guest

Courses New

Having fallen a vertical distance 'h' starting from rest, a ball rebounds elastically off an inclined plane. The plane is inclined at an angle 'x' with horizontal. At what distance from impact point will the ball rebound for the second time? Please reply as soon as possible

Having fallen a vertical distance 'h' starting from rest, a ball rebounds elastically off an inclined plane. The plane is inclined at an angle 'x' with horizontal. At what distance from impact point will the ball rebound for the second time?
Please reply as soon as possible

Grade:12

1 Answers

Vikas TU
14149 Points
6 years ago
Dear Student,
Speed with which it strikes the slanted plane=v 
=>v2=u2+2gh 
=>v=√2gh 
At the point when the ball strikes, by geometry the occurrence edge will be x and along these lines the reflection edge would likewise be x. 
considering the slanted plane as the even plane the body's ensuing movement can be considered as a shot movement with a point of 90-x with the flat with a speed √2gh since the crash is flexible. 
Separation it will affect for the second time= Range of the shot =R 
=>R=u2sin2/g 
=>R=2ghsin2(90-x)/g 
=>R=2hsin2.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More