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Forces 5N, 12N, and 13N are in equilibrium. If sin23 = 5/13, then the angle between 5N force and 13N force is? 23 67 90 113

Forces 5N, 12N, and 13N are in equilibrium. If sin23 = 5/13, then the angle between 5N force and 13N force is?
  1. 23
  2. 67
  3. 90
  4. 113

Grade:12th pass

2 Answers

BALAJI ANDALAMALA
askIITians Faculty 78 Points
8 years ago
These three forces can form right angled triangle.
Taking 13N as hypotenuse. The angle between 5N and 13N is 90-23 = 67 degrees.
Himadri
23 Points
6 years ago
Three forces are in equilibrium means net force is zero , according to question forces can form right angled triangle with 13N as hypotenuse,5N as altitude,12N as base.Since it is given that sin23=5/13 Therefore angle between 13N and 12N is 23° ,angle opposite to 12N force will be 67° , therefore the angle between 5 N a n d 13N will be (180°-67°)=113°

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