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`        An ornament weighing 36 g in air, weighs only 34 g in water. Assuming that some copper is mixed with gold to prepare the ornament, find the amount of copper in it. Specific gravity of gold is 19.3 and that of copper is 8.9.`
3 years ago

Jitender Pal
365 Points
```										Sol. Here, m0= mAu+ mcu= 36 g …(1)
Let V be the volume of the ornament in cm3
So, V × ρw× g = 2 × g
⇒(Vau+ Vcu) × ρw× g = 2 × g
⇒ (m/pau + m/pau) ρw × g = 2 × g
⇒ (pAu/19.3 + pAu/8.9) × 1 = 2
⇒8.9 mAu+ 19.3 mcu= 2 × 19.3 × 8.9 = 343.54 …(2)
From equation (1) and (2), 8.9 mAu+ 19.3 mcu= 343.54
⇒ 8.9(mAu + mCu/mCu = 2.225g)
So, the amount of copper in the ornament is 2.2 g.

```
3 years ago
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